How many grams is half a cup of semolina flour?
½ cup of semolina flour ≈ 81.5 g
Because one US cup of semolina flour weighs about 163 grams, half a cup of it is roughly 81.5 grams. Semolina is coarsely ground durum wheat and one of the heaviest flours by volume.
Recipes that list semolina flour in cups assume an average density. The figure above is a sensible typical value; if your recipe is sensitive, weigh on a kitchen scale — see our methodology.
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Semolina flour conversion chart
| Cups | Grams | Ounces | Tablespoons |
|---|---|---|---|
| ⅛ cup | 20.38 g | 0.719 oz | 2 |
| ¼ cup | 40.75 g | 1.44 oz | 4 |
| ⅓ cup | 54.33 g | 1.92 oz | 5.33 |
| ½ cup | 81.5 g | 2.87 oz | 8 |
| ⅔ cup | 108.7 g | 3.83 oz | 10.67 |
| ¾ cup | 122.3 g | 4.31 oz | 12 |
| 1 cup | 163 g | 5.75 oz | 16 |
| 1¼ cups | 203.8 g | 7.19 oz | 20 |
| 1½ cups | 244.5 g | 8.62 oz | 24 |
| 2 cups | 326 g | 11.5 oz | 32 |
| 3 cups | 489 g | 17.25 oz | 48 |
Other semolina flour conversions
* Conversion figures are typical average weights for one US customary cup (236.6 ml), based on the King Arthur Baking Ingredient Weight Chart and cross-referenced with the U.S. Department of Agriculture FoodData Central database. Actual weight varies with packing, brand and humidity — see our methodology.